- Introduction to Integrals
How to find the area under a curve?
You find the area under a curve y = f(x) above the x-axis between two vertical lines x = a and x = b by evaluating the definite integral of f(x) from a to b. First find the antiderivative F(x). Then compute F(b) minus F(a). If the boundaries are not given, set f(x) equal to zero to find where the curve crosses the x-axis.
The topic explained
Approximating with rectangles to exact integration
To determine the total area under a curve, picture slicing the region beneath the graph into vertical strips. You can approximate each strip as a rectangle whose height equals the value of the function at that point. Adding up the areas of these rectangles gives an estimate known as a Riemann sum.
As you increase the number of rectangles, their widths shrink toward zero. The gap between the flat tops of the rectangles and the smooth curve disappears. Taking the limit as the number of rectangles approaches infinity turns this sum into a definite integral, giving the exact geometric area.
The three-step method to calculate the area
First, determine the lower limit a and upper limit b. If the problem specifies boundaries like x = 1 and x = 4, use those numbers. If it asks for the area enclosed by the curve and the x-axis, set f(x) = 0 and solve for x to identify the x-intercepts.
Second, find an antiderivative F(x) of your function f(x). You do not need to include the constant of integration C because it cancels out when you subtract.
Third, apply the Fundamental Theorem of Calculus: compute F(b) - F(a). For example, to find the area under f(x) = 3x^2 from x = 1 to x = 3, take the antiderivative F(x) = x^3. Then evaluate F(3) - F(1) = 3^3 - 1^3 = 27 - 1 = 26 square units.
What to watch for: signs and boundaries
This direct method assumes f(x) remains on or above the x-axis across the entire interval from a to b. If the function drops below the x-axis, the definite integral assigns that lower section a negative value. To compute total geometric area, you must split the integral at every x-intercept and take the absolute value of any region lying below the axis.
Definite Integrals and Area Under a Curve Practice
Designed for 12th grade calculus students. Calculate the exact area bounded by the given curve, the x-axis, and the specified limits.
Free, no sign-up. The answer key prints on the second page. Regenerating a new worksheet on the same topic needs a free account.
Find the area under f(x) = 4 from x = 1 to x = 5.
Find the area under f(x) = 2x from x = 0 to x = 3.
Find the area under f(x) = 3x^2 from x = 1 to x = 2.
Find the area under f(x) = x^2 + 1 from x = 0 to x = 3.
Find the area under f(x) = 6x^2 - 2x from x = 1 to x = 3.
Find the area enclosed between the curve f(x) = 4 - x^2 and the x-axis.
Common questions
Why does adding more rectangles improve the area estimate?
Curved edges do not match flat rectangular tops. Using narrower rectangles reduces the excess area sticking above the curve or the empty gaps left underneath it, bringing the sum closer to the exact area.
Do I need to include + C when evaluating definite integrals?
No. When evaluating F(b) + C minus [F(a) + C], the two constants cancel out completely. Writing + C is therefore unnecessary for definite integrals.
What if the limits of integration are not given in the problem?
Find the limits by setting f(x) = 0 and solving for x. The solutions are the x-intercepts where the curve meets the x-axis, which serve as your lower and upper boundaries.
Can the area under a curve ever be negative?
Geometric area is always non-negative. However, a definite integral yields a negative value wherever a function dips below the x-axis. When finding geometric area for dipped sections, integrate those intervals separately and take their absolute values.

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