Introduction to Derivatives · Grade 12
How do you find the equation of a tangent to a graph?
Three steps. Find the y-coordinate of the point by substituting into the function, find the slope by substituting into the derivative, then put the point and the slope into the equation of a straight line. The order matters because the derivative gives a slope, never a point.
Learning objectives
- Find the equation of the tangent to a graph at a given point
- Find the point at which the slope of the tangent equals a given value
- Find the tangent that is parallel to a given straight line
The three steps
First, complete the point. A question usually gives only the x-coordinate, and the y-coordinate comes from substituting it into the function — into the function, not the derivative.
Second, find the slope. Differentiate, then substitute the same x into the derivative. The number that comes out is the slope of the tangent at that point.
Third, write the line. With a point and a slope, the equation of a straight line is immediate, and there is no further calculus involved.
Completing the point
Substituting into the wrong one of the two functions is the commonest error here, and it produces a line that is not tangent to anything.
A quick check: the point must lie on the graph. If you substitute its coordinates back into the original function and the two sides do not agree, the point is wrong before the slope is even considered.
When the slope is given instead of the point
Some questions give a slope and ask where the tangent has it. That reverses the work: set the derivative equal to that slope and solve for x.
There may be more than one answer, since a derivative can take the same value at several points. Find all of them, then complete each into a point and write a line for each.
Worked examples
Find the tangent to f(x) = x squared at x = 3
- Complete the point: f(3) is 9, so the point is (3, 9)
- Differentiate: 2x
- Substitute: the slope is 6
- Write the line through (3, 9) with slope 6
Answer: y = 6x − 9
Find the tangent to f(x) = x squared minus 4x at x = 1
- Complete the point: 1 minus 4 is minus 3, so (1, −3)
- Differentiate: 2x minus 4
- Substitute: 2 minus 4, so the slope is minus 2
- Write the line through (1, −3) with slope minus 2
Answer: y = −2x − 1
Where does f(x) = x squared have a tangent of slope 10?
- The slope is given, so set the derivative equal to it
- 2x equals 10
- Solve: x equals 5
- Complete the point: f(5) is 25
Answer: At the point (5, 25)
Common mistakes
- Substituting into the derivative to get the y-coordinate
- The point lies on the graph of the function, so its y-coordinate comes from the function. The derivative supplies the slope and nothing else.
- Writing the line with the x-coordinate as the intercept
- A point and a slope give the line through that point, not a line crossing the axis there. Substituting the point into the line equation and solving for the intercept avoids it.
- Stopping at one answer when the slope was given
- A derivative can take the same value at several points, so setting it equal to a slope can have more than one solution. Each solution is a separate tangent.
What to remember
- Point from the function, slope from the derivative.
- Complete the point before anything else.
- A point plus a slope gives the line.
- A given slope may have several solutions.